An electric pump rated 1.5 KW lifts 200kg of water through a vertical height of 6m in 10 secs: way is the efficiency of the pump?
1 answer
Question:
An electric pump rated 1.5 KW lifts 200kg of water through a vertical height of 6m in 10 secs: way is the efficiency of the pump?
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Answer:80%Explanation:Efficiency = Power output / Power input × 100 % To calculate efficiency we need to find power output of electric pump.We can use,Work done = Energy changeWork done per second = Energy change per secondWork done per second = PowerTherefore, Power = Energy change per second = Change in potential energy of water per second =mgh / t = 200× 10×6 / 10 = 1200 W = 1.2 kWNow use the first equation to find efficiency,Efficiency = [tex]\frac{1.2}{1.5}[/tex] × 100% = 80 %
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