An athlete prepares to throw a 2.0-kilogram discus. His arm is 0.75 meters long. He spins around several times with the discus at the end of his out-stretched arm so that the discus reaches a velocity of 5.0 m/s. What is the centripetal force acting on the discus? A.9.4 N B.14 N C.27 N D.66 N

2 answers
Question:

An athlete prepares to throw a 2.0-kilogram discus. His arm is 0.75 meters long. He spins around several times with the discus at the end of his out-stretched arm so that the discus reaches a velocity of 5.0 m/s. What is the centripetal force acting on the discus?
A.9.4 N
B.14 N
C.27 N
D.66 N

Answers

the centripetal force would be mv^2/rwhich is then equal to 2*5*5/0.75 that's 66 N

Answer:I am pretty sure the answer is "66N"Explanation:I've seen a lot of results on the internet saying the same thingIf this is not the answer, I am truly sorry and you can message me so that I can delete the question. Have a good day!

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