A virtual image is formed 17.0 cm from a concave mirror having a radius of curvature of 39.0 cm. (a) Find the position of the object. cm in front of the mirror (b) What is the magnification of the mirror?

1 answer
Question:

A virtual image is formed 17.0 cm from a concave mirror having a radius of curvature of 39.0 cm. (a) Find the position of the object. cm in front of the mirror
(b) What is the magnification of the mirror?

Answers

Explanation:Image distance, v = -17 cm (-ve for virtual image)Radius of curvature of concave mirror, R = 39 cmFocal length, f = -19.5 cm (-ve for a concave mirror)(a) Using mirror's formula as :[tex]\dfrac{1}{v}+\dfrac{1}{u}=\dfrac{1}{f}[/tex][tex]\dfrac{1}{u}=\dfrac{1}{f}-\dfrac{1}{v}[/tex][tex]\dfrac{1}{u}=\dfrac{1}{-19.5}-\dfrac{1}{(-17)}[/tex]  u = 132.6 cm    So, the object is placed 132.6 cm in front of the mirror.(b) Magnification of the  mirror, [tex]m=\dfrac{-v}{u}[/tex][tex]m=\dfrac{-17}{132.6}[/tex]m = -0.128 Hence, this is the required solution.

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