# A virtual image is formed 17.0 cm from a concave mirror having a radius of curvature of 39.0 cm. (a) Find the position of the object. cm in front of the mirror (b) What is the magnification of the mirror?

1 answer

###### Question:

A virtual image is formed 17.0 cm from a concave mirror having a radius of curvature of 39.0 cm. (a) Find the position of the object. cm in front of the mirror

(b) What is the magnification of the mirror?

(b) What is the magnification of the mirror?

## Answers

Explanation:Image distance, v = -17 cm (-ve for virtual image)Radius of curvature of concave mirror, R = 39 cmFocal length, f = -19.5 cm (-ve for a concave mirror)(a) Using mirror's formula as :[tex]\dfrac{1}{v}+\dfrac{1}{u}=\dfrac{1}{f}[/tex][tex]\dfrac{1}{u}=\dfrac{1}{f}-\dfrac{1}{v}[/tex][tex]\dfrac{1}{u}=\dfrac{1}{-19.5}-\dfrac{1}{(-17)}[/tex] u = 132.6 cm So, the object is placed 132.6 cm in front of the mirror.(b) Magnification of the mirror, [tex]m=\dfrac{-v}{u}[/tex][tex]m=\dfrac{-17}{132.6}[/tex]m = -0.128 Hence, this is the required solution.

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