A vibration platform oscillates up and down with a fixed amplitude of 8.1 cm and a controlled frequency that can be varied. If a small rock of unknown mass is placed on the platform, at what frequency will the rock just begin to leave the surface so that it starts to clatter? Hint: You should recall the condition that helps determine when two objects lose contact.

1 answer
Question:

A vibration platform oscillates up and down with a fixed amplitude of 8.1 cm and a controlled frequency that can be varied. If a small rock of unknown mass is placed on the platform, at what frequency will the rock just begin to leave the surface so that it starts to clatter? Hint: You should recall the condition that helps determine when two objects lose contact.

Answers

Answer:F = 0.02917hzExplanation:From the problem we could infer that it involves simple harmonic motion.For simple harmonic motion, maximum accelration(g) = Amplitude(A)×Angular velocity(w)²g = Aw²Simple harnonic motion= A sin(wt) Therefore, w = √g/Ag = 9.8m/s² and A = 8.1cmw = √9.8/8.1w = 1.0999rad/sTherefore, frequency (f) = w/2πF = 1.0999/2πF = 0.02917hz

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