A submarine is exploring the Pacific Ocean. At 502.5 feet below sea level, the water temperature is 63 1/4°F. The submarine dives down 115 feet deeper, and the water temperature drops by 2 1/5 °F. What were the elevation and the water temperature after the submarine dove? Assume that sea level is at 0 feet of elevation.
Write an expression to represent the water temperature after the submarine’s final dive. Then simplify the expression to find the temperature.
2 answers
Question:
A submarine is exploring the Pacific Ocean. At 502.5 feet below sea level, the water temperature is 63 1/4°F. The submarine dives down 115 feet deeper, and the water temperature drops by 2 1/5 °F. What were the elevation and the water temperature after the submarine dove? Assume that sea level is at 0 feet of elevation.
Write an expression to represent the water temperature after the submarine’s final dive. Then simplify the expression to find the temperature.
Answer:At the elevation 617.5 feet below the sea level temperature of the water was 61\frac{1}{20}°FStep-by-step explanation:At 502.5 feet below the sea level temperature of the water is 63\frac{1}{4}°FWhen submarine dives down 115 feet deeper, water temperature drops by 2\frac{1}{5}°FElevation after the submarine dove = -502.5 - 115 = -617.5 feetThis negative sign represents the elevation below the sea level.And the temperature will be = 63\frac{1}{4}-2\frac{1}{5} = \frac{253}{4}-\frac{11}{5} = \frac{1265-44}{20} = \frac{1221}{20} = 61\frac{1}{20}°FTherefore, at the elevation 617.5 feet below the sea level temperature of the water was 61\frac{1}{20}°F
answer from mariegammill
Answer:at the ellevation..................5.17Step-by-step explanation:
Which of the following is an equivalent simplified expression for 2(4x + 7) – 3(2x – 4) ?
A. x + 2
B. 2x + 2
C. 2x + 26
D. 3x + 10
E. 3x + 11
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