A sample of 54.0 g of methanol is heated from 25.0 °c to 35.0 °c. how much heat is required? the specific heat capacity of methanol is 2.48 j g–1 k–1.

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Question:

A sample of 54.0 g of methanol is heated from 25.0 °c to 35.0 °c. how much heat is required? the specific heat capacity of methanol is 2.48 j g–1 k–1.

Answers

The  amount of heat required   is calculated  using the below  formulaQ(heat) =M(mass) xC(specific heat capacity)x delta T (change in temperature)change in the temperature in kelvin=(35+273)- (25 +2730= 10Kc= 2.48 j/g/kmass= 54.0 gQ= 54.0 g x 2.48 j/g/k x 10k  = 1339.2  joules is required

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