A sample of 0.020 mole of oxygen gas is confined at 227°C and 0.50 atmospheres. What would be the pressure of this sample at 27°C and the same volume?
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Question:
A sample of 0.020 mole of oxygen gas is confined at 227°C and 0.50 atmospheres. What would be the pressure of this sample at 27°C and the same volume?
Answers
Answer:-0.3 atmExplanation:-Number of moles n = 0.020 molPressure P 1 = 0.5 atmTemperature T 1 = 227 C + 273 = 500 K We know the value of universal Gas constant R = 0.082 L atm K−1 mol−1 We use the relation PV = nRTV = nRT /PPlugging in the valuesV = 0.020 mol x (0.082 L atm K−1 mol−1 ) x 500 K / (0.5 atm)= 1.64 LNow the new temperature T 2 = 27 C + 273 = 300 K.Volume is same = 1.64 LNumber of moles n is same = 0.020 molOnce again we use the relation PV = nRTNew Pressure P = nRT / V = 0.020 x 0.082 L atm K−1 mol−1 x 300 K / 1.64 L = 0.3 atm
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