A monatomic ideal gas expands slowly to twice its original volume, doing 370 j of work in the process. part a find the heat added to the gas if the process is isothermal.
1 answer
Question:
A monatomic ideal gas expands slowly to twice its original volume, doing 370 j of work in the process. part a find the heat added to the gas if the process is isothermal.
Answers
The first law of thermodynamics says that the variation of internal energy [tex]\Delta U[/tex] of a gas is equal to the amount of heat Q supplied to the gas minus the work W done by the gas:[tex]\Delta U = Q-W[/tex]The variation of internal energy of a gas is:[tex]\Delta U = \frac{3}{2} n R \Delta T [/tex]As it can be seen, it depends only on the variation of temperature [tex]\Delta T[/tex]. Since for an isothermal process [tex]\Delta T=0[/tex], then [tex]\Delta U=0[/tex]. This means that the first law of thermodynamics becomes[tex]Q=W[/tex]and since the work done is 370 J, then the amount of heat is also 370 J: [tex]Q=370 J[/tex].
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