# A grocery store has two recycling machines outside. The first recycling machine took in 240 plastic bottles and 180 metal cans. The second took in 30 percent more plastic bottles but 10 percent less metal cans. The second machine recycled what percent more items than the first (rounded to the nearest percent)?

###### Question:

outside. The first recycling machine took in 240

plastic bottles and 180 metal cans. The second

took in 30 percent more plastic bottles but 10

percent less metal cans. The second machine

recycled what percent more items than the first

(rounded to the nearest percent)?

## Answers

Answer is 112%kinda skeptical about my answer but i am going to give it my best shot, sorry if i get it wrong.In percent-type questions I always go by this formula: not a % %original number : 100%new number : new %original number × new % = new number × 100%here, the original numbers are 240 and 180 and the new % is +30% and -10% now let plastic be P and metal be M and let's elaborate this a bit furtherplastic:the first recycling machine took in 240 plastic bottles while the second took in 30% more plastic bottles, what we have to do here is to find out how much bottles the second machine took in as a form of integer, which is the new number; let that new number be X, let's plug this in the formula[tex]240:100+30\\X:130 \\[/tex]notice: 130 is the new % [tex]240*130 = 100X\\31200 = 100X\\312=X[/tex]the second machine took in 312 plastic bottles, let's save this answer for latermetal:the first recycling machine took in 180 metal cans while the second took in 10% less plastic bottles, we do the same thing and find the new number, this time let it be Y:[tex]180:100-10\\Y=90[/tex]90 is the new % here; also, notice how sometimes you either add or subtract percents, depending on what the problem demands.[tex]180*90=100Y\\16200=100Y\\162=Y[/tex]Now we can conclude that the first recycling machine took in 240 plastic bottles and 180 metal cans and the second took in 312 plastic bottles and 162 metal cans.here comes the hardest bit to apprehend and the final part of this problem, "the second machine recycled what percent (%) more items than the first?"in other words, how much percent did the second machine recycle more.to find that percent, first we need to add the plastic and metal "items" of both machines individually and turn them into percents: let the first machine be A and second machine be B:A: 240+180=420B: 312+162=474again, using the same formula to find the new percent, let that percent be Z; plugging both A and B respectively:[tex]420:100\\474:Z[/tex][tex]420Z=474*100\\420Z=47400\\Z= 112.857[/tex]≈ 112% more items than the firstnow if you check the rounded up 112 and plug it back in to make sure of your answer: [tex]420Z=47400[/tex] you end up getting 47040, since it's rounded up, but when you plug the full 112.857 you get 47399.94, closest to 47400. Tip: when you plug in any value for check up, don't use the rounded up one.At last, those steps are actually fast, especially with that formula it's so important. the explanation seems intimidating so read it slowly and take your time. if you have any other questions, feel free to ask. also, let me know if you know a faster method to solve this question. <3