A company did a quality check on all the packs of trail mix it manufactured. Each pack of trail mix is targeted to weigh 9.25 oz. A pack must weigh within 0.23 oz of the target weight to be accepted. What is the range of rejected masses, x, for the manufactured trail mixes? x < 9.02 or x > 9.48 because |x − 0.23| + 9.25 > 0 x < 9.25 or x > 9.48 because |x − 9.25| > 0.23 x < 9.25 or x > 9.48 because |x − 0.23| + 9.25 > 0 x < 9.02 or x > 9.48 because |x − 9.25| >
2 answers
Question:
A company did a quality check on all the packs of trail mix it manufactured. Each pack of trail mix is targeted to weigh 9.25 oz. A pack must weigh within 0.23 oz of the target weight to be accepted. What is the range of rejected masses, x, for the manufactured trail mixes?
x < 9.02 or x > 9.48 because |x − 0.23| + 9.25 > 0
x < 9.25 or x > 9.48 because |x − 9.25| > 0.23
x < 9.25 or x > 9.48 because |x − 0.23| + 9.25 > 0
x < 9.02 or x > 9.48 because |x − 9.25| > 0.23
x < 9.02 or x > 9.48 because |x − 0.23| + 9.25 > 0
x < 9.25 or x > 9.48 because |x − 9.25| > 0.23
x < 9.25 or x > 9.48 because |x − 0.23| + 9.25 > 0
x < 9.02 or x > 9.48 because |x − 9.25| > 0.23
Answers
9.25 - 0.23 = 9.02 (It can't weigh less then this) 9.25 + 0.23 = 9.48 (It can't weigh more then this) rejected masses are : x < 9.02 and x > 9.48 D) x < 9.02 or x > 9.48 because |x − 9.25| > 0.23
Answer:The correct option is D) x < 9.02 or x > 9.48 because |x − 9.25| > 0.23Step-by-step explanation:Given:- Each pack of trail mix is targeted to weigh 9.25 oz. a pack must weigh within 0.23 oz of the target weight to be accepted.We need to find out the correct range of rejected masses, X for the manufactured trail mixes9.25 - 0.23 = 9.02 (It can't weigh less then this) 9.25 + 0.23 = 9.48 (It can't weigh more then this) Since, rejected masses are : x < 9.02 and x > 9.48 Only option A and D has condition x < 9.02 and x > 9.48 In option A) |x − 0.23| + 9.25 > 0this is wrong condition because it must be |x − 0.25| For Option D)Check:modulus |x − 9.25| > 0.23 express as - 0.23 > (x − 9.25) > 0.23Add 9.25 in above ,- 0.23 + 9.25 > (x − 9.25 + 9.25) > 0.23 +9.259.02 > x > 9.48 TrueSo, the correct option is D)x < 9.02 or x > 9.48 because |x − 9.25| > 0.23
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