A 420-turn circular coil with an area of 0.0650 m2 is mounted on a rotating frame, which turns at a rate of 22.3 rad/s in the presence of a 0.0550-T uniform magnetic field that is perpendicular to the axis of rotation. What is the instantaneous emf in the coil at the moment that the normal to its plane is perpendicular to the field

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Question:

A 420-turn circular coil with an area of 0.0650 m2 is mounted on a rotating frame, which turns at a rate of 22.3 rad/s in the presence of a 0.0550-T uniform magnetic field that is perpendicular to the axis of rotation. What is the instantaneous emf in the coil at the moment that the normal to its plane is perpendicular to the field

Answers

Answer:33.48 VExplanation:Parameters given:Number of turns, N = 420Magnetic field strength, B = 0.055 TArea, A = 0.065 m²Angular velocity, ω = 22.3 rad/sEMF induced in a coil is given as:EMF = -dΦ/dtwhere Φ = magnetic fluxMagnetic flux, Φ, is given as:Φ = B * N * A * cosωtEMF = -d( B * N * A * cosωt) / dtEMF = B * N * A * ω * sinωtwhere ωt = 90°Therefore:EMF = 0.055 * 420 * 0.065 * 22.3 * sin90°EMF = 33.48 V

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