A 40.0 kg block of lead is heated from -25°C to 200°C. How much heat is absorbed by the lead block? A. 2,354,000 J B. 1,170,000 J C. 56,891 J D. 10,650 J

1 answer
Question:

A 40.0 kg block of lead is heated from -25°C to 200°C.
How much heat is absorbed by the lead block?
A. 2,354,000 J
B. 1,170,000 J
C. 56,891 J
D. 10,650 J

Answers

Answer:B. 1,170,000 JExplanation:Given;mass of lead block, m = 40 kginitial temperature, t₁ = -25 ⁰Cfinal temperature, t₂ = 200 ⁰CThe heat absorbed the lead block is calculated as;H = mcΔtwhere;c is the specific heat capacity of lead =  130 J/kg⁰CH = 40 x 130 x (200 - (-25))H = 40 x 130 x (200 + 25)H = 40 x 130 x 225H = 1,170,000 JTherefore, the heat absorbed the lead block is 1,170,000 J

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