# A 180 pound person dives off of a 30 foot cliff. What is their velocity as they enter the water? Provide step by step

1 answer

###### Question:

A 180 pound person dives off of a 30 foot cliff. What is their velocity as they enter the water?

Provide step by step

Provide step by step

## Answers

Taking the sea level as reference for altitude, then, on top of the cliff the diver has only potential energy:Ep=m×g×h, where m is the diver's mass, g=9.8m/s² and h=30ft=9.144m is the cliff's height.At the sea level, the diver has kinetic energy: Ec=m×v²/2From energy conservation: Ec=Ep, resulting v=sqrt(2×g×h)=13.4m/sAnswer: v=13.4m/sNote that mass does not count in the final result.

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