A 180 pound person dives off of a 30 foot cliff. What is their velocity as they enter the water? Provide step by step
1 answer
Question:
A 180 pound person dives off of a 30 foot cliff. What is their velocity as they enter the water?
Provide step by step
Provide step by step
Answers
Taking the sea level as reference for altitude, then, on top of the cliff the diver has only potential energy:Ep=m×g×h, where m is the diver's mass, g=9.8m/s² and h=30ft=9.144m is the cliff's height.At the sea level, the diver has kinetic energy: Ec=m×v²/2From energy conservation: Ec=Ep, resulting v=sqrt(2×g×h)=13.4m/sAnswer: v=13.4m/sNote that mass does not count in the final result.
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