# 2. The surface area of a three-dimensional figure is the sum of the area measures for each of the figure's faces. Find the surface area of the cube shown below. 3 in. s=6e2 3 In Part 1: How many faces does the cube shown above have? (1 point) Part II: Find the area of one face of the cube shown above. Show your work. (2 points) Part III: Find the surface area of the cube shown above. Show your work. (2 points)

2 answers

###### Question:

2. The surface area of a three-dimensional figure is the sum of the area measures for each of the

figure's faces. Find the surface area of the cube shown below.

3 in.

s=6e2

3 In

Part 1: How many faces does the cube shown above have? (1 point)

Part II: Find the area of one face of the cube shown above. Show your work. (2 points)

Part III: Find the surface area of the cube shown above. Show your work. (2 points)

figure's faces. Find the surface area of the cube shown below.

3 in.

s=6e2

3 In

Part 1: How many faces does the cube shown above have? (1 point)

Part II: Find the area of one face of the cube shown above. Show your work. (2 points)

Part III: Find the surface area of the cube shown above. Show your work. (2 points)

## Answers

[tex]\color{plum}\tt \: Answer \: \: part \: \: 1 :[/tex]All cubes have six faces. Likewise, the cube shown above also has 6 faces.[tex]\color{plum}\tt \: Answer \: \: part \: \: 2 :[/tex]Length of side of one face of cube = 3 inchesArea of one face := Side × Side = 3 × 3= 9 inch²Therefore, the area of one face of this cube = 9 inch²[tex]\color{plum}\tt \: Answer \: \: part \: \: 3 :[/tex]Area of cube = sum of the area of all facesThen, the area of this cube :[tex] = 9 + 9 + 9 + 9 + 9 + 9[/tex][tex] = 9 \times 6[/tex][tex] = 54 \: \: {inches}^{2} [/tex]Therefore, the area of this cube = 54 inches²

Answer: 54Step-by-step explanation:

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