2. The area of a trapezium is 1080cm2. If the lengths of the parallelsides are 55.6 cm and 34.4 cm,then find the distance betweenthem.​

2 answers
Question:

2. The area of a trapezium is 1080
cm2. If the lengths of the parallel
sides are 55.6 cm and 34.4 cm,
then find the distance between
them.​

Answers

Answer:Therefore, the distance (height) is 24cm.Brainliest plzzzzzStep-by-step explanation:Area of trapezium = 1/2 × (a+b) × h *a and b are the parallel lengths Now we are going to find the distance, which is height (also known as 'h'). First, substitute the given values into the equation. 1080 = 1/2 × (55.6 + 34.4) × h Move the 1/2 over to 1080 and divide. 1080 ÷ 1/2 = (55.6 + 34.4) × h 2160 = (55.6 + 34.4) × h Add the numbers in the brackets. 2160 = 90 × h Move 90 over to 2160 and divide. 2160 ÷ 90 = h 24 = h

Step-by-step explanation:area = a+b/2×h1080=55.6+34.4/2×h1080×2=55.6+34.4h2160=90hh=2160/90h=24

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