# 2. The area of a trapezium is 1080cm2. If the lengths of the parallelsides are 55.6 cm and 34.4 cm,then find the distance betweenthem.

2 answers

###### Question:

2. The area of a trapezium is 1080

cm2. If the lengths of the parallel

sides are 55.6 cm and 34.4 cm,

then find the distance between

them.

cm2. If the lengths of the parallel

sides are 55.6 cm and 34.4 cm,

then find the distance between

them.

## Answers

Answer:Therefore, the distance (height) is 24cm.Brainliest plzzzzzStep-by-step explanation:Area of trapezium = 1/2 × (a+b) × h *a and b are the parallel lengths Now we are going to find the distance, which is height (also known as 'h'). First, substitute the given values into the equation. 1080 = 1/2 × (55.6 + 34.4) × h Move the 1/2 over to 1080 and divide. 1080 ÷ 1/2 = (55.6 + 34.4) × h 2160 = (55.6 + 34.4) × h Add the numbers in the brackets. 2160 = 90 × h Move 90 over to 2160 and divide. 2160 ÷ 90 = h 24 = h

Step-by-step explanation:area = a+b/2×h1080=55.6+34.4/2×h1080×2=55.6+34.4h2160=90hh=2160/90h=24

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